3w^2-4w-207=0

Solution for 3w^2-4w-207=0 equation:

3w^2-4w-207=0

a = 3; b = -4; c = -207;
Δ = b2-4ac
Δ = -42-4·3·(-207)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-50}{2*3}=\frac{-46}{6}
=-7+2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+50}{2*3}=\frac{54}{6}
=9
$